Tag Archive: Wager


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Below are photos of the worksheets that will help you study.

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Remember: exponential functions are not straight line.
They take the shape of a parabola. Parabolas look like the letter U. when you graph something with an exponent, it’s always curved.

Avogadro's number in e notation

Image via Wikipedia

Vocabulary

Scientific notation is all about how to write large and small numbers  as multiples of 10.

If your exponent is

POSITIVE: move decimal point to the LEFT.

NEGATIVE: move decimal point to the RIGHT.

You would write scientific notation using the following format.

_significant figure_ x 10 ^—-power

Examples

Write 6998000000 in scientific notation

1. Count the number of significant figures (all the numbers that are not zeros). There are four significant figures. These are the numbers that you will include in your scientific notation expression.

6998000000

2. Move your decimal place to the left until you reach the first and second number in your figure. The decimal should be placed between these two numbers.

6.998000000

3. Rewrite your answer in scientific notation

6.998 x 10 ^9  (pronounced as “six point nine nine eight times ten to the ninth power”)

When you write your answer in standard notation, you are converting your scientific notation expression into its original form. Let’s look at the example above. In scientific notation, it is written as 6.998 x 10 ^9; however, in standard form the number is written as 6998000000.

Example

7.75 x 10 ^-1    = 77.5

Move your decimal place once to the right.

Determine the solution set of a system of inequalities by following these five steps.

  1. Put your linear inequalities into slope-intercept form
  2. Determine whether your lines will be dashed (—–) or solid (——)
  3. Graph your linear inequalities
  4. Select a test point (such as (0, 0) to determine if the linear inequality is true or false
  5. Shade the TRUE side of the line

y < – x + 4

Solve each system of equations by using the graphing or substitution method.

1. y= x + 3          x – 2y = 0

substitute your first equation for the y-value in the second equation.

x – 2(x + 3) = 0 —-> x- 2x – 6 = 0 —–> -x – 6 = 0 —–> -x -6 + 6 = 0 + 6 —-> -x/-1 = 6/-1 —-> x = -6

substitute your x-value into the first equation.

y= -6 + 3 —-> y = -3

write your solution

Solution (-6, -3)

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